A) A small plastic bead is held stationary in the Earth\'s gravitational field b

Question

A) A small plastic bead is held stationary in the Earth's gravitational field by a downward-directed electric field. If the mass of the bead is 1.45g. What is the magnitude and sign of the charge on the bead if the electric field as a magnitude of 690 N/C? ( Be sure to consider the direction of the field.) Answer:
Q = ( ) C
B) What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight (on the earth)? Answer: E = ( ) N/C A) A small plastic bead is held stationary in the Earth's gravitational field by a downward-directed electric field. If the mass of the bead is 1.45g. What is the magnitude and sign of the charge on the bead if the electric field as a magnitude of 690 N/C? ( Be sure to consider the direction of the field.) Answer:
Q = ( ) C
B) What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight (on the earth)? Answer: E = ( ) N/C Answer:
Q = ( ) C
B) What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight (on the earth)? Answer: E = ( ) N/C Q = ( ) C
B) What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight (on the earth)? B) What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight (on the earth)? Answer: E = ( ) N/C

Explanation / Answer

field is downward.

E = - 690 N/C

balancing force on bead,

Fnet = Fe - m g = 0

and Fe = q E

q (-690) = 1.45 x10^-3 x 9.8

q = - 2.06 x 10^-5 C

magnitude = 2.06 x 10^-5 C

sign - negative

(B) Fe - mg = 0

q E = m g

(1.6 x 10^-19)(E) = (9.109 x 10^-31) (9.8)

E = 5.58 x 10^-11 N/C

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.