PLZ PLZ SOLve bOth the questios Using Coulomb\'s Law to Clean the Air Modern smo

Question

PLZ PLZ SOLve bOth the questios

Using Coulomb's Law to Clean the Air Modern smokestacks use devices called scrubbers to remove large amount of pollution in the form of small particles (soot). Scrubbers use a two steps process: electrons are first added to the soot particle, and an electric force then pulls the particle out of the smoke stream. Consider a soot particle of mass m_soot= 1.4 picograms (1.4e-12 kg), which corresponds to a diameter of a few micrometers. Some number of electrons have been added to give the particle a total charge q_soot. Suppose the collector has a total charge q_collector = 1.85e-06 C. If the separation between the collector and the soot particle is r = 0.2 m. What is the magnitude of q_soot (in units ofso that the electric force exerted on the particle is equal to its weight = mg ?. Use: g = 10 m/s^2, and k = 9E9 M m^2/C^2. How many electrons must be added to the soot particle ? electrons The charge of a single electron has a magnitude of e = 1.6 E-19 C, so our value of q_soot corresponds to: N = q_soot/e. In the figure above, the direction of the electrostatic force on a positive particle placed at point A is. In the figure above, the direction of the electrostatic force on a negative particle placed at point A is .

Explanation / Answer

Here ,

m= 1.4 *10^-12 Kg

q = 1.85 *10^-6 C

let the charge on the soot particles is Q

F = m * g = k * Q * q/r^2

1.4 *10^-14 * 9.8 = 9 *10^9 * 1.85 *10^-6 * Q/0.2^2

solving for Q

Q = 3.29 *10^-19 C

the charge on the soot particle is 3.29 *10^-19 C

number of electrons on the soot = Q/e

number of electrons on the soot = 3.29 *10^-19/(1.602 *10^-19)

number of electrons on the soot = 2

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Here , for the figure , as the electric field due to both points radially away from the charges , the net electric field at A will be towards RIGHT

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Here , for the figure , as the electric field due to both points radially towards from the charges , the net electric field at A will be towards upwards

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