The velocity, v, of a box sliding down a slope can be calculated as: v = (2xg (s
ID: 1843991 • Letter: T
Question
The velocity, v, of a box sliding down a slope can be calculated as:
v = (2xg (sin? - ? cos?))0.5
where g is gravity acceleration, x is the distance down the slope, ? is the coefficient of friction and ? is the angle of the slope. If g = 9.81 m/s2, x = 3 ft, ? = 0.1 (no units), and ? is 40o what is the velocity in miles per hour (mph)?
The velocity, v, of a box sliding down a slope can be calculated as:
v = (2xg (sin? - ? cos?))0.5
where g is gravity acceleration, x is the distance down the slope, ? is the coefficient of friction and ? is the angle of the slope. If g = 9.81 m/s2, x = 3 ft, ? = 0.1 (no units), and ? is 40o what is the velocity in miles per hour (mph)?
Explanation / Answer
velocity v =( (2* 3*0.3048*9.81*(sin40- 0.1*cos40))^(0.5))*(3600/1000) = 11.5 kmph= 11.5* 0.6214 mph =7.13mph
velocity v = 7.13mph
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