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You have completed the design of a new biofilter. Your design calls for the inst

ID: 1844902 • Letter: Y

Question

You have completed the design of a new biofilter. Your design calls for the installation of a sign adjacent to the biofilter that describes the biofilter and its importance in sustainable design. Your design calls for the center of the post for the sign to be installed at [3899666.17,11479887.94, 554.12] (Virginia State Plane South coordinates-given as N,E,Z). You are tasked with stakeout for the sign location (i.e. drive a stake at this coordinate to tell the contractor where to place the sign). Using the existing control points: Cl [3899686.752,11479882.287, 554.623], and C2 [3899656.989, 11479881.626, 554.087], you set-up your total station directly over point C2 (with height of instrument of 4.2'), and then backsight to Cl, zeroing the horizontal angle there (horizontal angle is tumed clockwise). What is the "shot" (i.e. the slope distance, vertical angle, and horizontal angle) you need to take in order to locate the stake. You have set the height of your prism to be 3.1'.

Explanation / Answer

we have existing control points = C1[3899686.752,11479882.287,554.623]

C2 [3899656.989,11479881.626,554.087

we have to setup our total station directly to the point C2

for which we need to find the shot (slope distance ,vertical angle horizonta angle )

for slope distance

m = (rise /run) x 100

we take rise = 4.2 and run =3.1

=> to find the slope distance

= (4.2 /3.1) x 100 => (1.3)100

= 130'

so the slope distance we got here is 130'

now for vertical angle

vertical angle s are the angle who are formed by the intersection of two lines

to find angle = height /(legnth +100)

angle= 4.2 / (3.1+100)

angle = 4.2/(103.1) => 0.04

so the vertical angle is = 0.04o

to find the horizontal angle

(height / legnth) +100

=> (4.2 / 3.1) +100 = 1.3 +100

=> 101.3

so the horizontal angle is = 101.3o

so the shot we got to locate the stake are

slope distance = 130'

vertical angle =0.04o

horozontal angle=101.3o

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