A medium-sized refinery has 80,000 components that must be evaluated for fugitiv

Question

A medium-sized refinery has 80,000 components that must be evaluated for fugitive emissions. Of these, 60,000 are connectors, 9000 are light liquid valves, 6000 are heavy liquid valves,4000 are gas valves, 340 are pressure relief valves, 400 are open-ended lines, 100 are light liquid process fluid contains 90 percent by weight organic compounds and 10 percent water.
a) Determine the fugitive emissions from this refinery using the average emissions approach?
B) assume that a screening survey of the components found that all of the open-ended lines, 30 percent of the valves, 25 percent of the connectors, and 20 percent of all of the other components emitted hydrocarbons in excess of 10,000 ppmv TOC. estimate the refinery's fugitive emissions using the screening ranges approach ?
C) the refinery decides to check its fugitive emissions using the EPA correlation approach. It determines that the screening values are as follows : valves, 50,000 PPMV, pump seal, 70,000 ppmv, connectors, 65,000 PPMV, flanges, 30,000 PPMV and open-ended lines, 450,000 ppmv. Assume all components leak. What is the estimated fugitive emissions rate using this procedure ? A medium-sized refinery has 80,000 components that must be evaluated for fugitive emissions. Of these, 60,000 are connectors, 9000 are light liquid valves, 6000 are heavy liquid valves,4000 are gas valves, 340 are pressure relief valves, 400 are open-ended lines, 100 are light liquid process fluid contains 90 percent by weight organic compounds and 10 percent water.
a) Determine the fugitive emissions from this refinery using the average emissions approach?
B) assume that a screening survey of the components found that all of the open-ended lines, 30 percent of the valves, 25 percent of the connectors, and 20 percent of all of the other components emitted hydrocarbons in excess of 10,000 ppmv TOC. estimate the refinery's fugitive emissions using the screening ranges approach ?
C) the refinery decides to check its fugitive emissions using the EPA correlation approach. It determines that the screening values are as follows : valves, 50,000 PPMV, pump seal, 70,000 ppmv, connectors, 65,000 PPMV, flanges, 30,000 PPMV and open-ended lines, 450,000 ppmv. Assume all components leak. What is the estimated fugitive emissions rate using this procedure ?
a) Determine the fugitive emissions from this refinery using the average emissions approach?
B) assume that a screening survey of the components found that all of the open-ended lines, 30 percent of the valves, 25 percent of the connectors, and 20 percent of all of the other components emitted hydrocarbons in excess of 10,000 ppmv TOC. estimate the refinery's fugitive emissions using the screening ranges approach ?
C) the refinery decides to check its fugitive emissions using the EPA correlation approach. It determines that the screening values are as follows : valves, 50,000 PPMV, pump seal, 70,000 ppmv, connectors, 65,000 PPMV, flanges, 30,000 PPMV and open-ended lines, 450,000 ppmv. Assume all components leak. What is the estimated fugitive emissions rate using this procedure ?

Explanation / Answer

A) Refinery average emission factors:

EQUIPMENT TYPE SERVICE EMISSION FACTOR(Kg/hr/source)

Valves Gas 0.0268

light liquid 0.0109

heavy liquid 0.00023

pressure relief valves gas 0.16

connectors all 0.00025

open ended lines all 0.0023

AVERAGE EMISSIONS APPROACH:

ETOC = FA x WFTOC x N

Where ETOC: Emission rate of TOC from all the equipment in the stream of a given equipment type ( in kg/hr)

FA= Applicable average emission factor for the equipment type (kg/hr/source)

=(60000 x 0.00025+9000x0.0109+6000x0.00023+4000x 0.0268+340x0.16+400x0.0023)/6

=46.16

WFTOC =Applicable averge emission factor for the equipment type

   =0.9

N:Number of pieces of to the applicable equipment for the stream

:100

(Kg/hr) ETOC = 46.16 X 0.9 X 100 = 418104

B) SCREEN RANGES APPROACH

ETOC= (FG x NG)

FG x NG : Applicableemission factors for sources with for screening values greater than or equal to 10,000 ppmv(Kg/hr/source)

: 400x0.01195+0.3x340x1.691+ 0.3x4000x0.2626 + 6000x0.3x0.00023 + 0.3x9000x0.0852 + 100x0.2x0.9

ETOC= 123.47 (Kg/hr)

EPA correlation approach:

equipment type

valves leak rate (kg/hr) = 2.29E - 06 x(SV)0.746

pump seals leak rate (kg/hr) = 5.03E-05x (SV)0.610

connecters leak rate(kg/hr) = 1.53E - 06 (SV)0.735

flanges leak rate(kg/hr) = 4.61E -06 (SV)0.703

Open ended lines leak rate (kg/hr) = 2.20E- 06x(SV)0.704

SV =screen value in ppnmv

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