A bridge has been constructed between the mainland and an island . the total cos
ID: 1845096 • Letter: A
Question
A bridge has been constructed between the mainland and an island . the total cost ( excluding tolls ) to travel across the bridge is expressed as ( C = 50 + 0.5 V ) , where V : is the number of Veh/hr , and C : is the Cost/Veh in cents . the demand for travel across the bridge is ( V = 2500 - 10 C )
a) Determine the volume of traffic across the bridge .
b) If a toll of 25 cents is added , what is the volume across the bridge ?
c) A toolbooth is to be added , thus reducing the travel time to cross the bridge , the new cost function is ( C = 50 + 0.2 V ) , Determine the volume of traffic the would cross the bridge .
d) Determine the toll to yield the highest revenue for demand and supply function in part (a) and the associated demand and revenue .
Explanation / Answer
By substituting the value of cost (C) from equation (1) to equation (2), we get the following:
V=2500 -10(50+0.5V)
V=2500-500-5V
6V=2000
V=333.33 vehicles/hour » 334 vehicles/hour
Therefore, the number of vehicles wanting to cross this bridge is 334 vehicles/hour.
2.If a 25 cent toll was added, what is the new volume crossing the bridge?
Adding 25 cents to the original cost we get,
C=50+0.5V+25
C=75+0.5V
Now, we have to substitute the value of C into the demand function in order to get the value of V.
V=2500-10(75+0.5V)
V=2500-750-5V
6V=1750
V=291.667 » 292 vehicles/hour.
Therefore, the new volume crossing the bridge will now be 292 vehicles/hour.
3. An additional toll booth changed the cost function to C=50+0.2V. Determine the new volume of vehicles wanting to cross this bridge.
Substituting the value new Cost into the demand function we can get the value of V.
V=2500-10(50+0.2V)
V=2500-500-2V
3V=2000
V=666.67 » 667 vehicles/hour
Therefore, the new number of vehicles wanting to cross this bridge is 667 vehicles/hour.
4.To determine the toll to yield the highest revenue for part (a)
We assume a toll rate at T. The new cost function will be C=50+0.5V+T. Since the revenue generated is the toll rate, T, time the volume, V, first we have to solve for V with the new cost function.
V=2500-10(50+0.5V+T)
V=2500-500-5V-10T
V=(2000-10T)/6
Since the revenue generated is R=T*V, we substitute the above expression into the revenue formula and differentiate with respect to T.
R=T*((2000-10T)/6)
R=(2000T-10T2)/6
Now,
(2000-10*2T)/6=0
T=100cents or $1.00
Therefore, T=$1.00 will yield the maximum revenue.
Now, R=(2000T-10T2)/6
R=(2000(100)-10(100)2)/6
R=16,666.67 cents/hour » $166.67per hour
Therefore, a toll of $1.00 will yield a revenue of $166.67 per hour.
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