Part A A bipolar transistor is connected to a resistive load as shown below. The

Question

Part A

A bipolar transistor is connected to a resistive load as shown below. The source Voltage V_CC is 60 V and R_L is 5 ohms. In the saturation region, the collector-emitter voltage V_CE is 5 V and beta is 6. While the transistor is in the saturation region, calculate the following:

a. Load current

b. Load power

c. Losses in the collector circuit

d. Losses in the base circuit

e. Efficiency of the circuit

Part B

For the transistor in Part A, compute the load current, load power, and efficiency of the circuit when the transistor is in the cutoff region. Assume that the collector current is 100 mA in the cutoff region.

A bipolar transistor is connected to a resistive load as shown below. The source Voltage V_CC is 60 V and R_L is 5 ohms. In the saturation region, the collector-emitter voltage V_CE is 5 V and beta is 6. While the transistor is in the saturation region, calculate the following: Load current Load power Losses in the collector circuit Losses in the base circuit Efficiency of the circuit For the transistor in Part A, compute the load current, load power, and efficiency of the circuit when the transistor is in the cutoff region. Assume that the collector current is 100 mA in the cutoff region.

Explanation / Answer

a) current = 55/5 = 11A

power = 121*5W

loss in collector = 60*11 - 121*5 = 55W

loss in base = i*v = (11/6)*Vbe

eff = 121*5 / (121*5 + 55 + loss in base)

b) current = 0.1A

power = 0.05W

eff = 0.05/ (6 + 0.1*vbe/6)

note: I think Vbe should be given, if not take it 0.7(check)

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