Find work done by a 3 step thermodynamic cycle, which consists of an initial pre

Question

Find work done by a 3 step thermodynamic cycle, which consists of an initial pressure 5x10^5 Pa, and volume 100cm^3. The first step brings it to a second state with pressure 2x10^5 Pa and volume 170cm^3. The second step brings it to a pressure of 3x10^5 Pa, and volume of 100 cm^3. The final step of the cycle brings it back to its initial conditions, 5x10^5 Pa, and volume 100cm^3. What is work done by the system in going through a complete cycle? Is the work positive or negative? (is work done by the system or to the system?) -> I know that the equation should be work=integral (P dV) from volume initial to volume final. But if i do that, then that means the work by first step = 2x5^5 (170) - 5x10^5 (100). If i do that for every step, i get a total work done by system = 0, and i don't think that's right....

Explanation / Answer

Well here we need to know the path that it takes to go from state 1 to state 2 to state 3. Coz work will depend upon the path. If its an adiabatic process, work transfer will be different than if its a isothermal process.

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