The tank is filled with water to a height of 2 m. Calculate the resultant force

Question

The tank is filled with water to a height of 2 m. Calculate the resultant force the water exerts on one of the sides of the tank. If oil is used in lieu of water, what depth should it reach to create the same resultant force? ?o= 900kg/m3. ?w= 1000 kg/m3.

The tank is filled with water to a height of 2 m. Calculate the resultant force the water exerts on one of the sides of the tank. If oil is used in lieu of water, what depth should it reach to create the same resultant force? ?o= 900kg/m3. ?w= 1000 kg/m3.

Explanation / Answer

pressure on top = 0 pr on bottom = density*g*height = 1000*9.81*2 = 19620 Pa Avg pr = (0+19620)/2 = 9180 Pa Force on one side = pr*area = 9180*(0.75*2) = 13770 N If oil is used, then force = 13770/1000*900 = 12393 N

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