The 5-kg wheel has a radius of gyration about its center of gravity G of kG=0.7m
ID: 1852155 • Letter: T
Question
The 5-kg wheel has a radius of gyration about its center of gravity G of kG=0.7m. The wheel is released from rest and rolls without slipping. The spring AB has a stiffness k = 1.20 N/m and an unstretched length of 0.5 m. When the wheel has rotated clockwise 90degrees from the position shown, what is its angular velocity and angular acceleration?
The 5-kg wheel has a radius of gyration about its center of gravity G of kG=0.7m. The wheel is released from rest and rolls without slipping. The spring AB has a stiffness k = 1.20 N/m and an unstretched length of 0.5 m. When the wheel has rotated clockwise 90degrees from the position shown, what is its angular velocity and angular acceleration?Explanation / Answer
present length o spring = 3.041m change in spring energy = 0.5*1.2*(3.041^2 - 2.5^2) = 1.798J 0.5*(5*0.7^2)*w^2 = 1.798 w = 1.211rad/s
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