(Assume r mercury = 13,560 kg/m 3 and r water = 997 kg/m 3 at P atm = 90 kPa) Th

ID: 1852532 • Letter: #

Question

(Assume rmercury= 13,560 kg/m3 and rwater= 997 kg/m3 at Patm = 90 kPa)

The pressure at the bottom of a tank of water is measured with manometer, hwater = 3.0 m and hmercury = 0.43 m. Find

a) the gage pressure at the bottom of the tank in kPa.

A) 18

B) 28

C) 38

D) 48

E) 58

b) the absolute pressure at the bottom of the tank in kPa.

A) 118

B) 128

C) 138

D) 148

E) 158

c) the gage pressure at the interface between water and mercury in kPa.

A) 27

B) 37

C) 47

D) 57

E) 67

d) the absolute pressure at the interface between water and mercury in kPa.

A) 117

B) 127

C) 137

D) 147

E) 157

for mercury p=rough*g*h =13560*9.8*0.43 =57141.84kpa for water p=rough*g*h =997*9.8*3 =29311.8kpa tatal pressure p=p1+p2 p=29311.8+57141.84 =86453.64

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