B. How many individuals in the pedigree are known to be homozygous dominant for
ID: 185254 • Letter: B
Question
B. How many individuals in the pedigree are known to be homozygous dominant for the allele that causes the trait indciated by the dark symbols?
C. How many individuals in the pedigree are potenitally homozygous dominant?
D. What is the probability that the next child of I-1 and I-2 will have the trait indicated by the dark symbols?
a. 3/4
b. 1
c. 0
d. 1/2
e. 1/3
f. 1/4
g. 2/3
E. What is the probability that II-3 is homozygous for the dominant allele?
a. 2/3
b. 1/2
c. 3/4
d. 1/3
e. 1/4
f. 0
F. III-1 and III-2 plan to marry and have five children. What is the probability (P) that one child will have the trait illustrated by the dark symbols and four will not? NOTE: This is not a chi-square calculation!
a. 0.05 P < 0.10 b. 0.30 P c. 0.20 P < 0.30 d. 0.10 P < 0.20 e. P < 0.05 Pedigree 1 40 2012 Pearson Education, Inc. Refer to this pedigree as you consider the questions below Part A What pattern of inheritance is indicated by the dark symbols in this pedigree? O autosomal dominant sex-linked dominant sex-linked recessive autosomal recessiveExplanation / Answer
Part A: sex linked dominant disorder as most of the females are getting affected.
B: 9 individuals have a homozygous dominant trait.
C. 12 individuals are potentially homozygous dominant.
D. 2/3 as out of 6 children's 4 are afffected so probability is 4/6 =2/3.
E. 1/ 2 as II -3 is having two female kid and one is affected out of it, so probability is 2/4 =1/2.
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