To apply the kinetic equations of motion to rigid bodies undergoing translation.

Question

To apply the kinetic equations of motion to rigid bodies undergoing translation. When a rigid body undergoes translation, each particle of the body has the same acceleration aG = a, where aG is the acceleration of the center of mass. Also, the rotational equation of motion reduces to The scalar equations of motion for rectilinear translation, where all particles travel in parallel straight-line paths, become where and are the sum of the forces in the x and y directions, respectively, m is the mass, and is the sum of the moments about the center of gravity. The scalar equations of motion for curvilinear translation, where all particles travel in parallel curved paths, become where the subscripts n and t denote the normal and tangential directions of motion, respectively. The moment equation for both types of translation. can be replaced by a summation of moments about an arbitrary point A, where the moment of maG must be accounted for with the following equation: where the term is the moment of maG The bottle in the figure rides on a conveyor belt. (Fjgure1) If the belt's acceleration is a = 7.70ft/s2 , determine the minimum coefficient of static friction that prevents the bottle from slipping. Assume that the bottle is wide enough that it will slip on the belt without tipping. Express your answer numerically to three significant figures. This question will be shown after you complete previous question(s). This question will be shown after you complete previous question(s).

Explanation / Answer

ma = u * mg so a= u*g u = a/g = 7.7 ft/s2 /32.2 ft/s2 = 0.239 = 0.24 approx please rate

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