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While traveling on a flatbed railroad car at 6m/s a soccer player kicks a ball i

ID: 1855066 • Letter: W

Question

While traveling on a flatbed railroad car at 6m/s a soccer player kicks a ball intending to hit the center of a stationary horizontal target directly on the tracks. If the target is 2m below the flatbed and the kicking velocity is 15m/s, at what angle must the ball be kicked and how long before or after the player passes the target must the ball be kicked? Presume the ball can only be kicked up into the air and not down into the railroad car. If there is more than one solution, find any valid solution.

Explanation / Answer

follow this example 2pi / 3600 = w = angular velocity from the formula w = delta Angle / Delta time delta = Change in 1.745329252 x 10^-3 rad/s Now we will use V = RW 0.082 x 1.745329252 x 10^-3 = 4.431169987 x 10^-4 m/s nice shhot dude