2. A vessel of volume V (6 liters) contains water along with its saturated vapor

Question

2. A vessel of volume V (6 liters) contains water along with its saturated vapor under a pressure of 40 atmospheres and a temperature of 250 C. The specific volume of the water vapor under these conditions is v_g = 50 liters/kg. The total mass of the contents in the vessel is m = 5.0 kg. Assuming a reasonable value v_f for the specific volume of liquid water, determine a. The mass of the vapor b. The volume of the vapor

Explanation / Answer

First find the specific volume of the total water and vapor mixture. v = V/m (6L/5kg). assume a v_f of about 1.1 L/kg. using the equation for quality and specific volumes, v = v_f + x(v_g - v_f) (6/5) = 1.1 + x(50 - 1.1) ==> x = 0.002 then use quality and mass equation m_vapor = x(m_total) (a) m_vapor = (.002*5) ==> m_vapor = 10.2 g then use V_vapor = (v_g)*(m_vapor) (b) V_vapor = (50)*(0.0102) ==> V_vapor = 0.511 L

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