(*Question) At room temperature (23 o C), a cylinder of steel has a diameter of
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Question
(*Question) At room temperature (23oC), a cylinder of steel has a diameter of 15.02 mm, which is too large to fit into a 15 mm diameter hole in a steel block. In order to make the fit, the steel block is heated, thereby expanding the dimension of the hole.
Estimate the temperature (in oC) to which the block must be heated, so that the hole and cylinder have the same diameter. The coefficient of thermal expansion for steel is alphasteel = 12 x 10-6/oC.
Round your answer to the nearest whole number.
Explanation / Answer
as the expansion required is from 15mm to 15.02 mm,i.e., dL =15.02-15=0.02
a=12 x 10e-6 =1/LxdL/dT
dT= 1/LxdL/12 x 10e-6
dT = 0.02/(12*10e-6x15)
dT = 111.11'C
final temperature = 23+111.11= 134.11'C
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