Air contained in a rigid tank undergoes a reversible adiabatic process from stat

Question

Air contained in a rigid tank undergoes a reversible adiabatic process from state 1 (T1 = 332 K, P1 = 183 MPa) to state 2 (T2 = 718 K, P2 = 910 MPa). Determine the total heat transfer per unit mass (kJ/kg) for this porcess.

Determine the change in specific entropy (kJ/kg-K) for air undergoing a process from state 1 (T1 = 326 K, P1 = 247 kPa) to state 2 (T2 = 854 K, P2 = 485 kPa). Assume constant specific heats as given below (DO NOT USE the ideal gas tables).

Cp = 1.005 kJ/kg-K

Cv = 0.718 kJ/kg-K

Correct Answer: 0.7742 ± 1%

Determine the change in specific entropy (kJ/kg-K) for air undergoing a process from state 1 (T1 = 300 K, P1 = 115 kPa) to state 2 (T2 = 1,196 K, P2 = 844 kPa). Assume variable specific heats (use the ideal gas tables). Your answers may vary slighly (< 1%) from the given answer.

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