I need details with answers Given the graph of the spectral emissitivity of a di
ID: 1858800 • Letter: I
Question
I need details with answers
Explanation / Answer
a)total emissivity=0.3*f(0-3micro m)+0.6*(1-f(0-3micro m)),
f(0-3micro m)=3*10^-6*T=3*10^-6*1000=3*10^-3 ,
hence total emissivity=0.3*3*10^-3+0.6(1-0.003)=0.5991 ans
d)Q=0.5991*5.67*10^-8*T^4=1200
T=433K
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