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A helical compression spring is made of No. 18 (.0147 in) wire having a torsiona

ID: 1858865 • Letter: A

Question

A helical compression spring is made of No. 18 (.0147 in) wire having a torsional yield

strength of 108 kpsi. It has an outside diameter of ½ in and has 14 active coils.

a. Find the maximum static load corresponding to the yield point.

b. What deflection would be caused by the load from (a) above.

c. Calculate the scale of the spring.

d. If the spring has one dead turn at each end, what is the solid height ?

e. What should be the length of the spring so that when it is compressed solid, the

stress will not exceed the yield point?

Explanation / Answer

Torsional yield=8PC/pie*D^3

C=6

108*10^3=8*P*6/3.14*0.5^3

P=883.125

B)Deflection= 8*P*C^3/Gd

=8*883.125*6^3/G*0.5

=84780/G

C)Scale,C=6

D)Solid height= Nt*D=15*0.5=7.5

This is all I can help..!!

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good Luck..!!!


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