solve the first question and this is the link for the image if you can see it ht
ID: 1860310 • Letter: S
Question
solve the first question and this is the link for the image if you can see it http://postimg.org/image/x8yckk9l9/
A 5 kg ball is released as shown 6 sec later it hits the rough surface (e = .75 ) where upon its bounces, would it clear the wall? The 155 th beam of radius of 8'' is supported by the edge of the table and a spring that was stretched 0.75'' before being attached at B. Determine the reactions Ax and Ay immediately upon the removal of the table. what will be the omega of the beem when it attains the horizontal configuration? knowing that the velocity of dollar D is 20''/sec uparrow, determine omega AD omega EB VA How far away from the red light should the driver going at 90 mph apply his brakes so as not to ensure any instabilities to the unsecured load he is transporting?Explanation / Answer
e is the ratio of the final energy and the initial enrgy
i.e
final Kinetic enrgy / intial potential enrgy = .75
as the ball hits after 6 sec so height
S = .5 x g x t^2 = .5 x 9.8 x 36 = 176.4m
so intial potential energy = mgh = 5 x 9.8 x 176.4 = 8643.6 J
final KE = .5 x m x v^2
but
final KE/ initial PE = .75
so final KE = 6482.7 J
.5 x 5 x v^2 = 6482.7
v = 50.9 m/s
the velocity makes an angle of 65 degrees with the surface on which it lands
max height = v^2 sin ^2 theta / 2g
= 50.9 ^2 sin 65^2/2 x 9.8
= 108.57m
= 356.2 ft
range = v^2 sin 2theta / g = 50.9^2 sin 130 / 9.8 = 202.5 m = 664.3 ft
thus the ball clearly clears the wall
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