a passenger automobile is advertised as having a fuel economy rating of 29 mi/ga

Question

a passenger automobile is advertised as having a fuel economy rating of 29 mi/gal for highway driving .express the rating in the units of km/lclass="chg-suggest-term">

Explanation / Answer

1 gallon = 3.785 L ; 1 mi = 1.609 km

therefore 1 mi/ga = (1.609/3.785) km/L = 0.425

29 mi/ga = 29*0.425 km/L =12.32 km/L = fuel economy rate in km/L

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