8. You have 2 genes A and B that independently assort. You cross two plants with
ID: 186084 • Letter: 8
Question
8. You have 2 genes A and B that independently assort. You cross two plants with the following: AA BB x aa bb. a. what proportion of the F1 progeny are homozygous at both loci (5 pts) b. After letting the F1 self-pollinate, what proportion of the F, progeny from this cross match the parental genotypes (5 pts)? c. What proportion of the F, progeny are homozygous for the b allele (5 pts)? 9. You have 2 genes A and B that independently assort and are located on different chromosomes. You have a cell from an individual that is heterozygous for both genes. Draw the chromosomes with these genes on them as they would appear in the following cell cycle phases. Use lines for chromosomes/chromatids and circles to denote the centromeres. (10 pts) (A) G1 phase (B) G2 phase
Explanation / Answer
Please find the answers below:
Answer 8: According to the information, the cross is made between parents with genotype AABB * aabb. The Punnett square can be formulated as below:
Genotype: All AaBb
Phenotype: All dominant type.
Answer part a: It can be seen from the Punnett square that none of the offsprings will be homozygous at both positions.
Answer part b: When F1 will self-pollinate, the following Punnett square can be formulated:
Thus, it can be seen that only a single offspring of F2 will have genotype AABB and single offspring will bear genotype aabb, like the parents. Similarly, 4 offpsrings will bear the genotype AaBb like the F1 class.
Answer part c: It can be seen from the Punnett square that only 3 offsprings of F2 will be homozygous for allele b.
AB AB ab AaBb AaBb ab AaBb AaBbRelated Questions
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