clearly show SKETCH, PROPERTY TABLE, MASS & ENERGY BALANCE EQUATIONS FOR EACH. a
ID: 1861274 • Letter: C
Question
clearly show SKETCH, PROPERTY TABLE, MASS & ENERGY BALANCE EQUATIONS FOR EACH.a) A rigid tank containing 20 kg of NITROGEN GAS (N2) at 1.0 bars and -26.43 oC is heated until the temperature reaches 200 oC. The final pressure and volume of the N2 are _______ kPa &_______ m3 . b) A rigid tank with a volume of 5.0 m3 contains ARGON GAS at -16 oC. The ARGON GAS absorbs 2500 kJ of external heat transfer causing the temperature to reach 160 oC. The total mass of the ARGON is ____________ kg. The initial and final pressures are _________ kPa and ________ kPa.
c) A rigid tank containing 20 kg of AIR at 6.0 bars and 140 oC is cooled causing the pressure to fall to 4.0 bars. The final temperature is _____ oC. The total heat transfer out of the system = _______ kJ
d) Twenty kilograms (20 kg) of NEON GAS contained in a piston-cylinder device initially at 6.0 bars and 140 oC is cooled at constant pressure to 273 K. The system work = ________ kJ and total transfer = ____________ kJ. clearly show SKETCH, PROPERTY TABLE, MASS & ENERGY BALANCE EQUATIONS FOR EACH.
a) A rigid tank containing 20 kg of NITROGEN GAS (N2) at 1.0 bars and -26.43 oC is heated until the temperature reaches 200 oC. The final pressure and volume of the N2 are _______ kPa &_______ m3 . b) A rigid tank with a volume of 5.0 m3 contains ARGON GAS at -16 oC. The ARGON GAS absorbs 2500 kJ of external heat transfer causing the temperature to reach 160 oC. The total mass of the ARGON is ____________ kg. The initial and final pressures are _________ kPa and ________ kPa.
c) A rigid tank containing 20 kg of AIR at 6.0 bars and 140 oC is cooled causing the pressure to fall to 4.0 bars. The final temperature is _____ oC. The total heat transfer out of the system = _______ kJ
d) Twenty kilograms (20 kg) of NEON GAS contained in a piston-cylinder device initially at 6.0 bars and 140 oC is cooled at constant pressure to 273 K. The system work = ________ kJ and total transfer = ____________ kJ.
Explanation / Answer
a)use the ideal gas equation
pv=nRT
n= no of moles of nitrogen = 20000/28 =1427.88 mol
R = universal gas constant = 8.314 j/K-mol
T = temperature = 273 - 26.43 = 246.57 K
v =volume
p = pressure = 1bar = 101325 pa
p1v1= nRT1
=>v1 = 1427.88 * 8.314 *246.57/101325 = 28.89 m3
using the equation ideal gas equation we get
p1v1/T1 = p2v2/T2
since it is a rigid tank hence it has a constant value
=> p1/T1 = p2/T2
p2 = 1*473/246.57 = 1.92 bar
V2 = 28.89 m3 or 29 m3 approx
similarly for b)
v1 = 5m3
T1 = 273-16 =257 K
Energy absorbed Q = 2500 kj
T2 = 273+160 = 433 K
You use equations for an ideal gas:
pV = NkT = nRT
U = CvNkT = Cv nRT
where:
Cv is a constant dependent on temperature (e.g. equal to 3/2 for a monatomic gas for moderate temperatures)
U is the internal energy
p is the pressure
V is the volume
n is the amount of gas (moles)
R is the gas constant, 8.314 J
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