In the absence of compressed liquid property tables it is common to approximate

Question

In the absence of compressed liquid property tables it is common to approximate properties by using the saturated liquid values. The purpose of this exercise is to compare actual values to the approximate values. Compare the values of specific volume (v), internal energy (u), and enthalpy (h) for water at 10 MPa and 25C using the compressed liquid tables and the saturated liquid approximation. What are the percent errors associated with the approximation?  What does the error and the percent error change to when the proper approximation for the enthalpy is used? Please put the final answer in table form. In the absence of compressed liquid property tables it is common to approximate properties by using the saturated liquid values. The purpose of this exercise is to compare actual values to the approximate values. Compare the values of specific volume (v), internal energy (u), and enthalpy (h) for water at 10 MPa and 25C using the compressed liquid tables and the saturated liquid approximation. What are the percent errors associated with the approximation?  What does the error and the percent error change to when the proper approximation for the enthalpy is used? Please put the final answer in table form.

Explanation / Answer

percent error

It is your estimate minus the true value divided by the true value and multiplied by 100.

So, % error = (estimate - actual) / actual * 100, in absolute value.

For example, if you estimate that there are 90 jelly beans in a jar when there are actually 130 your percentage error is:
(90-130)/130 * 100 = -40/130 * 100 = -0.308*100 = -30.8%

After absolute value, the answer is simply 30.769, or 30.8%

The heat energy which a solid absorbs when it melts is called the enthalpy and is usually quoted on a molar basis. (The word fusion means the same thing as

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