Using a typical venturi, such as is shown in Fig 8 - 5 assume that the diameter

Question

Using a typical venturi, such as is shown in Fig 8 - 5 assume that the diameter of the pipe is 2 inches at point 1 and 1 inch at point 2. If the manometer is filled with mercury and the deflection is x is 2.5 inches, what is the approximate flow rate of water through the ven-turi? What is the flow velocity at point 1 and at point 2 in the pipe?

Using a typical venturi, such as is shown in Fig 8 - 5 assume that the diameter of the pipe is 2 inches at point 1 and 1 inch at point 2. If the manometer is filled with mercury and the deflection is x is 2.5 inches, what is the approximate flow rate of water through the ven-turi? What is the flow velocity at point 1 and at point 2 in the pipe?

Explanation / Answer

Apply the bernouil equation across the venturimeter

P1 +1/2rho V1^2 =P2 +1/2rho V^2

or, P1 - P2 = 1/2rho(V1^2 -V2^2) using contuinity equation

pressure difference can be measyre dusing 'X' in the manometer.

the flow rate Q related to the manometer reading X , by bernoulli's equation is gaiven by

Q=[A2/{(1- (d2/d1)^4}^0.5][2gX(rho(manometer)- rho(water)/rho(water))]^0.5

where, A2= area at point 2

d1 and d2= diameter at point 1 and point 2 respectively

X= difference in the manometer

Using contninity equation ; A1V1= A2v2

we can find velocity at poitn 1 and point 2

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