The uniform disk of mass m 2 = 7.8 kg pivots freely on the cart of mass m 1 = 4.
ID: 1862496 • Letter: T
Question
The uniform disk of mass m2 = 7.8 kg pivots freely on the cart of mass m1 = 4.1 kg. Determine the acceleration a of the assembly and the angular acceleration ? of the disk under the action of the force P = 64 N applied to a cord wrapped securely around the disk. The acceleration is positive if up the slope, negative if down. The angular acceleration is positive if counterclockwise, negative if clockwise.
Explanation / Answer
We know the Force = mass x acceleration
acceleration of the assembly 64/(7.8+4.1)=5.3778 (along the direction of application of force)
in vector representation 5.3778 (cos16 i + sin 16 j)= 5.1698i + 1.4824j m/s^2
Moment of inertia of disk mr^2/2 = 0.22464 kg m^2
We know that torque = moment of inertia X angular acceleration
Torque = force x displacement =15.36 Nm
Angular acceleration = 68.37606 rad/s^2 (clockwise)
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.