causes albinism, 1. In humans, the a allele is recessive to the A allele. a enta

Question

causes albinism, 1. In humans, the a allele is recessive to the A allele. a entation. In a small population while A produces normal skin pigm which is at Hardy-Weinberg people is an albino. equilibrium, 100 out of every 10,000 A. What is the frequency of the a allele? B. What is the frequency of the A allele? C. What frequency of people in this generation are hom ozy gous recessive? D. How many people in the next generation will be heterozygous if the population size stays the same? 2. In humans, the p allele is recessive to the P allele. P allows normal metabolism, while p causes phenylketonuria. In a population at Hardy-Weinberg equilibrium, 256 out of every 10,000 people suffer from phenylketonuria. A. What is the frequency of the p allele? B. What is the frequency of the P allele? C. What frequency of people are homozygous for normal metabolism? D. What frequency of people are heterozygous? E. How many people out of 10,000 are heterozygous for normal metabolism? F. How many copies of the P allele are there in 10,000 people?

Explanation / Answer

1. 100 out of 1000 individuals are albino which means they are homozygous recessive 'aa'.

Phenotypic frequency of aa = 100÷ 1000 = 0.1.

A. Frequency of allele a = aa= q2= 0.1, q = 0.31.

B. P +q = 1.

Frequency of allele A = P = 1- q = 1- 0.31 = 0.69.

Therefore frequency of allele A = P = 0.69.

C. Frequency of people who are homozygous recessive 'aa' = 0.1.

D. Number of individuals heterozygous in the next generation are 2pq = 2× 0.69 x0.31 = 0.427

0.427 x 1000 = 427.

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