D Question 16 3 pts Newton\'s 2nd Law of Motion. Three forces, one of 99.0 N dir
ID: 1863796 • Letter: D
Question
D Question 16 3 pts Newton's 2nd Law of Motion. Three forces, one of 99.0 N directed to the right, the second of 33.0 N directed to the left, and the third of 45.0 N directed to upward, act simultaneously on an object with a mass of 65.0 kg. What is the direction of the resultant acceleration (in degrees) of the object? Note: Round your final answer to 3 sig. fig. Do NOT write units. D Question 17 2 pts Friction. A 54.0 kg crate initially at rest on a horizontal floor requires a 175 N horizontal force to set it in motion. Calculate the coefficient of static friction,u between the crate and the floor. Note: Round your final answer to 3 sig. fig. Do NOT write units.Explanation / Answer
16)
Net force along x:
Fx = 99 - 33 = 66 N
Net force along y:
Fy = 45 N
Direction of acceleration = direction of force
= arctan(Fy/Fx)
= 34.3 (degrees)
17)
force of friction f = F = 175
Also, f = umg
Equating both:
umg = 175
=> u = 175/mg
= 175/(54*9.8)
= 0.331
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