Problem 20.48 3 of 16 PartA Constants Two insulated wires perpendicular to each

Question

Problem 20.48 3 of 16 PartA Constants Two insulated wires perpendicular to each other in the same plane carry currents as shown in (Figure 1). Assume that I -10 A and d 16 Ccm Find the magnitude of the net magnetic field these wires produce at point P if the 10 A current is to the right (Current (a) in the figure). Express your answer in teslas to two significant figures. Submit Figure 1 of 1 Part B Find the magnitude of the net magnetic field these wires produce at point Q if the 10 A current is to the right (Current (a) in the figure). Express your answer in teslas to two significant figures. 0 8.0 cm 10 A 8.0 cimm d P Submit Request Answer

Explanation / Answer

the equation for magnetic field due to current carrying wire is

B = uo I/ 2 pi r

(a)at point p net magnetic field due to both wires is

B = uo/ 2pi ( 10/0.08 + 10/0.16) = 37.5 * 10^-6 T( into the page)

rounding to two significnat

B = 38 * 10^-6 T

(b)at point Q net magnetic field due to both wires is

B = uo/ 2pi ( 10/0.08 + 10/0.16) = 37.5 * 10^-6 T( out of the page)

rounding to two signigficant

B = 38 * 10^-6 T

(c)

at point p net magnetic field due to both wires is if the current 10A is left

B' = uo/ 2pi ( 10/0.08 - 10/0.16) = 12.5 * 10^-6 T( out of the page)

rounding to two significant

B' = 12 * 10^-6 T

(D)at point Q net magnetic field due to both wires is if the current 10A is left

B' = uo/ 2pi ( 10/0.08 - 10/0.16) = 12.5 * 10^-6 T( into the page)

roudnign to two significant

B' = 12 * 10^-6 T

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