Problem 20.23 Part A Singly ionized (one electron removed) atoms are accelerated

Question

Problem 20.23 Part A Singly ionized (one electron removed) atoms are accelerated and then passed through a velocity selector consisting of perpendicular electric and magnetic fields. The electric field is 157 V/m and the magnetic field is 3.14x102 T. The ions next enter a uniform magnetic field of magnitude 1.76x10-2 T that is oriented perpendicular to their velocity How fast are the ions moving when they emerge from the velocity selector? m/s u= Submit Request Answer ? Part B If the radius of the path of the ions in the second magnetic field is 17.2 cm, what is their mass? kg Submit Request Answer

Explanation / Answer

speed of electron in velocity selector is

v= E/B

=157/3.14 * 10^-2

=5000 m/s

(b)

centripetal force balanced by magnetic force

mv^2/R = Bqv

R = mv/qB

m = RqB/v

= (0.172)(1.6 * 10^-19) (1.76 * 10^-2)/5000

=9.68 * 10^-26 kg

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