E) 3.14 x 10 m (5) In problems 4, the resistance of 100m-long wire is: A) zero B
ID: 1864309 • Letter: E
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E) 3.14 x 10 m (5) In problems 4, the resistance of 100m-long wire is: A) zero B) 1.072 ? 2.14 D) 4.28 ? E) 6.4262 (6) An AC voltage is given by the following equation: V- 170 sin(314 rad/sec) t, where Vis measured in volts and t in seconds: A) the rms voltage is 170 volt and the frequency is 314 Hz. B) the rms voltage is 170 volt and the frequency is 50 Hz. C) the rms voltage is 120 volt and the frequency is 314 Hz. D) the rms voltage is 120 volt and the frequency is 50 Hz E) the rms voltage is zero and the frequency is zero. (7) In problems 6, if a 100 2 resistor is connected to the given AC voltage: A) both the peak current and the rms current are zero. B) the peak current is 1.7 A and the rms current is 1.2 A. C) the peak current is 1.2 A and the rms current is 1.7 A D) the peak current is 85 A and the rms current is 60 A E) the peak current is 60 A and the rms current is 85 A. J NAEINI, PHY1322, Test 2. Summer2018Explanation / Answer
5] data of 4 is required
6] Vrms = 170/ sqrt 2 = 170*0.707 = 120 V
f = w/2pi = 314/(2*3.14) = 50 Hz
option d
7] peak current = Vpeak/R = 170/100 = 1.7A
rms current = Vrms/R = 120/100 = 1.2A
option b is correct.
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