l. Induced currents Acopper wire loop is placed in a uniform magnetic field as s
ID: 1864621 • Letter: L
Question
l. Induced currents Acopper wire loop is placed in a uniform magnetic field as shown. Determine whether there would be a current through the wire of the loop in each case below. Explain your answer in terms of magnetic forces exerted on the charges in the wire of the loop. A. The loop is stationary. The loop is moving to the right. The loop is moving to the left. B. Suppose that the loop is now placed in the magnetic field of a solenoid as shown. Determine whether there would be a current through the wire of the loop in each case below. If so, give the direction of the current. Try to explain any current in terms of magnetic forces exerted on the charges in the wire of the loop. 1. The loop is stationary. The loop is moving toward the solenoid. The loop is moving away from the solenoid. 2. For each case in which there is an induced current, determine: The direction of the magnetic moment of the loop. (Hint: Find the direction of the magnetic field at the center of the loop due to the induced current in the loop. The magnetic moment is a vector that points in this same direction.) Whether the loop is attracted toward or repelled from the solenoid Whether the force exerted on the loop tends to increase or to decrease the relative motion of the loop and solenoid.Explanation / Answer
I am answering first question.
A) In constant magnetic field, flux through the loop will be constant. Thus, in each case, the loop is stationary, the loop is moving towards right, or the loop is moving towards left, the fux would still be constant and hence by Faraday's law, no voltage or current would be induced.
B) i) If the loop is stationary, the flux would be constant through the loop and hence no current would be produced.
ii) If the loop moves towards the solenoid, field through the loop will increase and hence the magnetic flux (as field is more near the solenoid). Therefore, current will be produced.
By Lenz law, the direction of current would be clockwise as seen from the solenoid end.
iii) It is just the opposite case of above, field decreases this time, and current will be produced according to Faraday's law, and by Lenz law, the direction would be anti-clockwise as seen from solenoid end.
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