Consider two widely separated conducting spheres, 1 and 2, the second having fiv

Question

Consider two widely separated conducting spheres, 1 and 2, the second having five times the diameter of the first. The smaller sphere initially has a positive charge q 3.00×10-o C, and the larger one is initially uncharged. You now connect the spheres with a long thin wire. How are the final potentials VI and V2 of the spheres related? Find the final charge q1 5.00x10-7 c You are correct. Your receipt no. is 161-8771 Find the final charge q2 .000003 C Submit Answer You have entered that answer before Incorrect. Tries 6/100 Previous Tries What is the ratio of the final surface charge density of sphere 1 to that of sphere 2? 5.00

Explanation / Answer

Since both are connected by wire ,potential of both wire will be same

V1=V2

q1=already calculated=5*10^(-7)

q2=q-q1=25*10^(-7)

surface density=charge /area

ratio=(q1/q2)*(r2/r1)^2=5

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