Pg 6. 0.50kg and the _ct 19 Block I has mssm, block 2 has mass m asadius 0.05m.

Question

Pg 6. 0.50kg and the _ct 19 Block I has mssm, block 2 has mass m asadius 0.05m. When m is released from rest it falls 0.8m in seconds without the cord slipping on the pulley. (3) a) What is the linear acceleration of the block? b) What is the magnitude of the tension T? c) Calculate the moment of Inertia of the disk. 20. A horizontal pipe 0.10m in diameter has a smooth reduction to a pipe 0.05m in diameter. If the inlet speed is 8m/s, (2) a) What is the speed of water at the other end? And b) What is the flow rate of water through the pipe?

Explanation / Answer

(a) As given

S=0.8 m

t=5 sec

a=2*S/t^2=0.064 m/s^2

(b)0.5*9.8-T2=0.5a

T2=4.868N

(c)T1=m1*a=0.02944

Let moment of inertai is I

(T2-T1)*R=I*a/R

we got

I=0.189 kgm^2

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.