A parallel-plate capacitor made of circular plates of radius 80 cm separated by

Question

A parallel-plate capacitor made of circular plates of radius 80 cm separated by 0.25 cm is charged to a potential difference of 500 volts by a battery. Then a sheet of polyvinyldienedifluoride film is pushed between the plates, completely filling the gap between them. How much additional charge flows from the battery to one of the plates when the polyvinyldienedifluoride film is inserted?
Dielectric constant for some materials:

Explanation / Answer

here,

radius , r = 80 cm = 0.8 m

potential differnce , V = 500 V

d = 0.25 cm = 0.0025 m

intial capacitance , C0 = area * e0 /d

C0 = pi * 0.8^2 * 8.85 * 10^-12 /( 0.0025) F

C0 = 7.1 * 10^-9 F

the intial charge stored , Q0 = C0 * V

Q0 = 500 * 7.1 * 10^-9 C

Q0 = 3.56 * 10^-6 C

K = 11

final capacitance , C = K * C0

final charge stored , Q = V * C

Q = V * K * C0

Q = 39.16 * 10^-6 C

the additional charge , dQ = Q - Q0

dQ = 3.56 * 10^-5 C

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