17. The distance between two conducting plates are decrease by a factor 2, the c

Question

17. The distance between two conducting plates are decrease by a factor 2, the capacitor will a) increase by a factor of 2 d) decrease by a factor of 4 b) decrease by a factor of 2 c) increase by a factor of 4 18. In a semi-conductor, what moves to conduct current? a) Electron b) Hole (Positive) charge c) Both a) & b) d) neutrons 19·?!tage is defined as the per unit a)) Work, charge b) work, time c) volts, charge d) potential difference 20. Combination of three electrons and three neutrons has _ _charge a) -1.6x10 19C b)-3.2X101"c c)4.8x10c d) 4.8X10 C

Explanation / Answer

17) We know that for a parallel plate capacitor,

C = kA / d

where A is area, d is distance between plates.

so, we can say that capacitance is inversely proportional to distance between plates. It means when distance is decreases by a factor of 2, the capacitance will increase by same factor.

18) Current is conducted in semiconductors through electrons and holes ( option c)

19) You already did that

20) The charge on neutron is zero. The electron has a charge as -1.6e-19 C. So, 3 electrons will have a charge of 3*(-1.6e-19) = -4.8e-19 C

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