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Eile Edit View History Bookmarks Iools Help G Google × GEile Edit View History Bookma/X e Physics question! Chegg.com × ?EXTRA CREDIT: Rolling Reprise × + https://www.webassign.net/web/Student/Assignment-Responses/submitde Search IIV Most Visited Getting Started Lemon Grove Inciden... AssignIment Scoring Your last submission is used for your score 1. 1015 points| Previous Answers My Notes Ask Your Teach A thin rod has a mass of 2.10 kg and is 0.44 m long. It is pressed into a thin hollow wheel (the diameter of the wheel is also 0.44 m): the mass of (just) the empty wheel is 1.90 kg. The combined object rolls along the floor so that its linear velocity is 4.700 m/s. It rolls without slipping and encounters a 20° ramp. What is the combined moment of inertia of the object about its center? 0.126 As it rolls up the ramp, there will be an instant when the rotational KE of the object will be exactly 9 J: At that moment, what is its linear velocity? 2.63 m/s. At that moment, to what vertical height from the floor has it risen? 0.545 Submit Answer Save ProgressPractice Another Version ? Mozilla Firefox seems slow to start. Learn How to Speed It Up Don't Tell Me Again X 06:52 p ENG 15/07/18

Explanation / Answer

c)

Total mass= 2.10+1.90= 4.00kg, Total moment of Inertia = I = 0.126kg*m^2 , Linear velocity at the bottom = v= 4.700m/s. radius = r= 0.44/2= 0.22m

Let us use law of conservation of energy

PEi+KEi= PEf+KEf

PEi+(KElinear +KErotational )= PEf+KEf

0+ 1/2mv^2 + 1/2I?^2 = mgh

1/2mv^2 + 1/2I(v/r)^2 = mgh

h=[1/2mv^2 + 1/2I(v/r)^2]/mg

h=[1/2*4.00*4.7^2+1/2*0.126*(4.7/0.22)^2]/(4.00*9.8)

h= 1.86m

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