An amusement park ride has a vertical cylinder with an inner radius of 4 m, whic
ID: 1865916 • Letter: A
Question
An amusement park ride has a vertical cylinder with an inner radius of 4 m, which rotates about its vertical axis. Riders stand inside against the carpeted surface and rotate with the cylinder while it accelerates to its full angular velocity. At that point the floor drops away and friction between the riders and the cylinder prevents them from sliding downward. The coefficient of static friction between the riders and the cylinder is 0.83. What minimum angular velocity in radians/second is necessary to assure that the riders will not slide down the wall?
Explanation / Answer
static friction force balanced by weight of rider
fs = F_g
us F_N = mg
us F_c= mg ( normal force is balnced by centripetal force)
us ( mv^2/r) = mg
us v^2/r = g
us ( rw)^2/r = g
w= sqrt g/ us r
= sqrt 9.8/0.83(4)
= 1.71 rad/s
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