4. One body of mass m1 2.018 kg is launched vertically with an initial velocity

Question

4. One body of mass m1 2.018 kg is launched vertically with an initial velocity v1 5 m/s. The body will reach the maximum height h after a period of time th. A second body of mass m2-1.776 kg is launched at a 30 angle (as shown in the figure below) with an initial velocity v2-10 m/s. The second body will reach the maximum height h2 after a period of time t2. (g- 9.80 m/s) a. Determine the maximum height for each of the bodies (h and h2). b. Determine the ratio between hi and h2 (h/ h2). c. Determine t2 /ty ratio. Neglect air friction and explain your answers. h1 v1 5 m/s 0 30 h2

Explanation / Answer

a)

h1 = v1^2/(2*g)

= 5^2/(2*9.8)

= 1.28 m

h2 = (v2*sin(theta))^2/(2*g)

= (10*sin(30))^2/(2*9.8)

= 1.28 m

b) h1/h2 = 1.28/1.28

= 1

c) t1 = 2*v1/g

= 2*5/9.8

= 1.02 s

t2 = 2*v2*sin(theta)/g

= 2*10*sin(30)/9.8

= 1.02 s

t2/t1 = 1.02/1.02

= 1

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