Your friend (mass 60.0 kg ) is standing on the ice in the middle of a frozen pon

Question

Your friend (mass 60.0 kg ) is standing on the ice in the middle of a frozen pond. There is very little friction between her feet and the ice, so she is unable to walk. Fortunately, there is a light rope tied around her waist and you stand on the bank holding the other end. You pull on the rope for 3.50 s and accelerate your friend from rest to a speed of 5.40 m/s while you remain at rest.

Part A

What is the average power supplied by the force you applied?

Your friend (mass 60.0 kg ) is standing on the ice in the middle of a frozen pond. There is very little friction between her feet and the ice, so she is unable to walk. Fortunately, there is a light rope tied around her waist and you stand on the bank holding the other end. You pull on the rope for 3.50 s and accelerate your friend from rest to a speed of 5.40 m/s while you remain at rest.

Part A

What is the average power supplied by the force you applied?

Explanation / Answer

W = 1/2 m (v22 - v12)

P = W / t

=  m (v22 - v12) / 2 t

= [60(5.402 - 0)] / [2 * 3.5]

average power supplied = 250 W

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