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Problem 20.31 Constants Part A A paralelplate capacitor is constructed of two ho

ID: 1866241 • Letter: P

Question

Problem 20.31 Constants Part A A paralelplate capacitor is constructed of two hotzontal 12.4 cm-diameter cicular plases. A 16 g plastic bead, with a charge of 40 nC s suspended between the two plates by the force of the electric field between them Which plate, the upper or the lowet is postively changed? O Upper Lower OIt is impossible to t Submit est Answer ?PartB What is the charge on the positive plate7 Express your answer to two signifticans Sures and inelude the appropriate units qValue Submt Provde Feedback

Explanation / Answer

Let us first calculate electric field & potential difference between two plates,

Fe=Fg

qE=mg

E=mg/q

E=(1.5*10^-3*9.8)/(4.0*10^-9)

E=3.675*10^6 N/C

V= Ed ---------------(1)

C=?0A/d -------------(2)

q=CV --------------(3)

Plug (1) and (2) in (3),

q=( ?0A/d)*(Ed)

q= E?0A

Plug values,

q=(3.675*10^6)*(8.85*10^-12)*(?*0.124^2)

q=1.6*10^-6 C

q=1.6 µC

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