Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

(896) Problem 7: A square surface of side length L and parallel to the y-z plane

ID: 1868761 • Letter: #

Question

(896) Problem 7: A square surface of side length L and parallel to the y-z plane is situated in an electric field given by E(x, y, z) = E0[i + (yj + zk)/ VV+z2) ]. The square's sides are parallel to the y- and z-axes and it is centered on the x-axis at position Px.I positive x-direction. is a unitless constant. Refer to the figure. The x- axis points out of the screen ts normal vector points in the ©theexpertta.com 50% Part (a) Integrate to find an expression for the total electric flux through the square surface in terms of defined quantities and enter the expression Grade Summary 0% 100% Attempts remaining: 6 4 5 6 % per attempt) detailed view Submit I give up! Hints: 2% deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback. 50% Part (b) For L= 4.4 m, Eo= 144.2 V/m, and = 0.15, find the value of the flux, in units of volt·meter

Explanation / Answer

The electric field has thre components in x, y and z directions. The x component will be perpendicular to the square, while y and z componenet will be parallel to the surface of the square. Hence the y and z components will not be cutting through the square surface and thus will not contribute for any electric flux through the square. The net electric flux throuth the square will only be due to x component of the electric field. So y and z components are irrelevant for our flux calculation.

x component of electric field is constant and is independent of position.

Ex = E0

Total flux through the square = L2E0

= L2E0 ANS (a)

(b) After putting the values

= (4.4)2 x 144.2

= 2791.712 volt.meter ANS (b)