In mice, a mahogany coat color allele is dominant over the tan coat color allele

Question

In mice, a mahogany coat color allele is dominant over the tan coat color allele. In a population of mice, the frequency of the allele for mahogany coat color is 0.19 and the frequency of the allele for tan coat color is 0.81. What would the genotypic frequencies be if the population is in equilibrium? ___=Frequency of homozygous dominant individuals ___=Frequency of heterozygous individuals ___=Frequency of homozygous recessive individuals How many individuals would you expect of each genotype in a population of 100 mice. ___=Number of HomoDom individuals ___=Number of Hetero ___=Number of HomoRecess

Explanation / Answer

Frequency of the allele encoding mahogany coat color (M) = 0.19

Frequency of the allele encoding tan coat color = 0.81

Frequency of homozygous dominant genotype (MM) = p2 = (0.19) (0.19) =0.036

Frequency of homozygous recessive genotype (mm) = q2 = (0.81) (0.81) = 0.656

Frequency of heterozygous genotype (Mm) = 2pq = 2 (0.19) (0.81) = 0.308

Number of homozygous dominant mice in population of 100 individuals = 100 (0.036) = 31

Number of homozygous recessive mice in population of 100 individuals = 100 (0.656) = 66

Number of heterozygous mice in population of 100 individuals = 100 (0.308) = 31

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