Problem #1 (show your work) (26 pts): During your physics lab you are walking in

Question

Problem #1 (show your work) (26 pts): During your physics lab you are walking in a straight line to demonstrate a new, improved sonic ranger. You are instructed to move back and forth in a straight line. The ranger is sct up to measure positive position if you are to the right of the center of the room, and ncgative position if you are to the left of the center of the room. As you move, the device produces the following graph of velocity vs. time. (Plcase note: it's velocity, not position!) +velocity A. (5 pts) Att-4.5 sec, which way are you moving? Make sure to justify why 4 m/s next to yur choice for full credit. +2 m/s i) To the right ii) To the Icft iii) You are at rest att-4.5 sec. time (s) 1 2 3 4 5 iv) We cannot conclude from this graph which way you are moving att 4.5 sec. B. (5 pts) If you start from xo= 0 m at 1-0 s what can you conclude about your position at the instant t 1 s? Make sure to justify why next to yur choice for full credit. i) Position is definitely positive ii) Position is definitely negative. iii) Position is definitely zero. iv) We cannot conclude whether position is positive, negative or zero from the in formation give C. (5 pts) What is your acceleration at t 3 s? Make sure to include units, sign, equations, and box your final answer. 3 ? Make sure to inchude D. (5 pts) What was the magnitude of your total displacement between t0 s and units, equations, and box your final answer. 3.5 s? Make sure to include units, sign, E. (6 pts) what was your average velocity between t-2 s and equations, and box your final answer.

Explanation / Answer

(a)At t= 4.5 s, the velocity of the object is -2 m/s.So the object is moving to the left.So option (ii) is correct.

(a)At t= 1 s, the velocity of the object is 4 m/s.So  the position is definitely positive.So option (i) is correct

(c) a= slope of graph from t=2 to t=3

a=(0-4)/(3-2)

a=-4 m/s2

(d)Distance= area under velocity time graph

d= (4x2)+1/2 (3-2)(4)

d= 10 m

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