Where did -8nC and +4nC come from in step 2? College Physics |(3rd Edition) Chap

Question

Where did -8nC and +4nC come from in step 2?

College Physics |(3rd Edition) Chapter 20, Problem 16P Bookmark Show all steps: Problem Object A, which has been charged to +10 nC, is at the origin Object B, which has been charged to -20 nC, is at (x, y)- (0.0 cm, 2.0 cm). What are the magnitude and direction of the electric force on each object? Step-by-step solution Step 1 of 4 Use Coulomb's law to solve for the magnitude and direction of electric force on a point charge due to the other The expression for the magnitude of electric force on charge a, due to charge , is Here, k is electric constant andr is separation between two charges The expression for the magnitude of electric force on charge 92 due to charge is, Thus, ' Comment Step 2 of 4 The figure showing the positions and directions of forces on 4.0 nc and -8.0 nc is given below (0.0 cm, 2.0 cm) -8.0 nC 21 12 +4.0 nC Comment Step 3 of 4A Convert the unit for charge from nC to C %-+4.0 nC

Explanation / Answer

They wanted to show you the way of solving these kind of problems.

The main part is step 1, that is how to apply the formula and which formula should be applied in which case.

They have taken a example to show the steps. But by mistake they took another problem and mixed the charge values with it.

You need not to worry. Just replace the charges with the given values as in question.

Just concentrate on the concept. And it can be solved for any values of charge and distance.

Thank you.

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