A capacitor with capacitance C = 6.00×10-3 F is initially uncharged. It is in se

Question

A capacitor with capacitance C = 6.00×10-3 F is initially uncharged. It is in series with a source of Emf of 4.00 volts, a resistor R, and a switch ás shown in the figure below. At t=0, the switch is closed. The graph below shows the potential difference across the capacitor as function of t, the time elapsed since the switch closed. 7 6 4 2 1 0 1 2 3 45 6 789 Time t (in seconds) Calculate the value of R. Note that the curve passes through a grid intersection point. (in ohm) 5.44 × 102 |5.55×102 |5.66 x 102 |5.78 × 102 |5.89 x 102 |6.01x102 6.13x102 6.25x102 Submit Answer Tries 0/20 What can you tell about the maximum power dissipated in R? The maximum power dissipated in R occurs at... :t-infinity Submit Answer Tries 0/20

Explanation / Answer

the potential difference inceases as v = E*[1-e^-(t/RC)]

from the graph

at time t = 5 s

v = 3 v

E = 4 v

C = 6*10^-3 F

3 = 4*(1-e^-(5/(R*6*10^-3)))

resistance R = 6.01*10^2

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part(B)

maximum power is dissipated at t = 0

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