STANDARD VIEW PRINTER VERSION BACK NEXT Chapter 22, Problem 069 Two particles, e

Question

STANDARD VIEW PRINTER VERSION BACK NEXT Chapter 22, Problem 069 Two particles, each with a charge of magnitude 12.5 nC, are at two of the vertices of an equilateral triangle with edge length 3.0 m. What is the magnitude of the electric field at the third vertex if (a) both charges are positive and (b) one charge is positive and the other is negative? (a) Number (b) Number Click if you would like to Show Work for this question: Units Units Open Show Work LINK TO TEXT LINK TO SAMPLE PROBLEM VIDEO MINI-LECTURE By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor.

Explanation / Answer

Here ,

a) magnitude of electric field due to each charge will be same at the third vertex , let the electric field due to each charge is E

E = k * Q/d^2

E = 9 *10^9 * 12.5 *10^-9/3^2

E = 12.5 N/C

Now , if both charges are positive , angle between electric field due to each charge is 60 degree

net electric field = 2 * E * cos(theta/2)

net electric field = 2 * 12.5 * cos(30 degree)

net electric field = 21.6 N/C

the net electric field at the third vertex is 21.6 N/C

b) if one of the charge is negative

angle between electric field due to each charge is 120 degree

net electric field = 2 * E * cos(theta/2)

net electric field = 2 * 12.5 * cos(60 degree)

net electric field = 12.5 N/C

the net electric field at the third vertex is 12.5 N/C

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