physics content of your answer as well as on its structure, completeness and mat

Question

physics content of your answer as well as on its structure, completeness and mathematical correctness. Remember, as with everything, neatness counts. 1: A projectile is fired with an initial speed of 30.0 m/s at an angle of 60.0°above the hori- zontal on a long flat field. Determine (a) The maximum height reached by the projectile. (b) The time it takes to get to the maximum height. (c) The total time in the air. (d) The total horizontal distance covered. (e) The velocity of the projectile 1.50 s after firing distance. 2: On page 75 of Serway&Vuille; problem 7 3: On page 76 of Serway & Vuille problem 17 4: On page 78 of Serway&Vuille; problem 43

Explanation / Answer

Ans:-

Given data: V= 60m/s, =30deg, t 4s

Let’s determine the vertical and horizontal components of the object’s initial velocity.

Vertical = 60 * sin 30 = 30 m/s, Horizontal = 60 * cos 30 = 51.96m/s

As the object moves to its maximum height, its vertical velocity decreases from 30 m/s to 0 m/s at the rate of 9.8 m/s^2 each second. The horizontal velocity is constant. So, the velocity at the highest point is 51.96

To determine the straight line distance, we need to determine the object’s vertical and horizontal position at 4 seconds. Use the following equation to determine its vertical position.

h = vi * t + ½ * a * t^2, vi = 30 m/s, a = -9.8 m/s^2
h = 30 * 4 + ½ * -9.8 * 4^2 = 41.6 meters
To determine the horizontal position, use the following equation.

d = vi * t, vi = 60 * cos 30
d = 60 * cos 30 * 4 = 240 * cos 30
This is approximately 208 meters.

To determine the straight line distance, use the following equation.

d = (Vertical^2 + Horizontal^2)
d = [41.6^2 + (240 * cos 30)]^2 = 44,930.56
This is approximately 212 meters.

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