A stone is thrown horizontally at 45.0 m/s from the top of a very tall cliff. Ca

Question

A stone is thrown horizontally at 45.0 m/s from the top of a very tall cliff. Calculate its horizontal position and vertical position at 2.00 s intervals for the first 10.0 s .

Part A

Calculate the horizontal x and vertical y positions at time t = 2 s.

Part B

Calculate the horizontal x and vertical y positions at time t = 4 s.

Part C

Calculate the horizontal x and vertical y positions at time t = 6 s.

Part D

Calculate the horizontal x and vertical y positions at time t = 8 s.

Part E

Calculate the horizontal x and vertical y positions at time t = 10 s.

Explanation / Answer

stone is thrown horizontally so

initial vertical velocity. v0y = 0

and v0x = 45 m/s

ay = - 9.8 m/s^2

ax = 0

y = v0y t + ay t^2 /2 = - 4.9 t^2

and x = (v0x) t = 45 t

(A) t = 2 : x = 90 m , y = - 19.6 m

(B) t = 4, x = 180 m, y = - 78.4 m

(C) t = 6, x = 270 m , y = - 176.4 m

(D) t = 8 s, x = 360 m, y = - 313.6 m

(E) t = 10 s, x = 450 m, y = - 490 m

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