On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball wit

Question

On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a 6 iron. The free-fall acceleration on the moon is 1/6 of its value on earth. Suppose he hits the ball with a speed of 29 m/s at an angle 25 above the horizontal.

A.) How much farther did the ball travel on the moon than it would have on earth?

Express your answer to two significant figures and include the appropriate units.

B.) For how much more time was the ball in flight?

Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

Ans:-

Given data v= 29m/s, = 25deg

  Sin25=0.423
cos25=0.906

d=vixt-1/2at^2
0=(29*0.423)*t - 5/6 t^2 (gravity on earth=10)
t=14.72s

v*t=distance
29*0.906*14.72=386.75m

on earth
0=(29*0.423)t-5t^2
t=2.45 s

29*0.906*2.45=64.46m

386.75/64.46=5.9998 = 6times more

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